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chris w

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  1. I'm still the only one with a working paralleler with auto-switch off
  2. Time will tell.....................
  3. chris w


    I have 4 of the "Waterbuoys" (as seen on Dragon's Den). I haven't had cause to use one in anger yet but the end caps have all stayed in on mine and one got wet in the rain and didn't go off. (Maybe it never will ). A tenner each. Chris
  4. If we listed all your errors and mistakes on here Pete, we'd have to start a special section just to keep it manageable (that would include your latest paralleler circuit of course, which STILL isn't working). You didn't earn the epithet of "Gibbo's glove-puppet" for nothing.
  5. Er............... that's because it was designed for MY boat that does have an alternator controller. I designed it for ME and published it because I thought others might be interested. The other difference is that it works. Chris That's after a total of 12 posts from you. Once you're into long trousers, you can start to debate with the big boys, who've spent a lifetime in electronics. Till then, keep sucking your lolly.
  6. If you rae not willing to "tinker", you shouldn't be playing around anyway with your electrical systems. A lead-acid battery is a deadly weapon in the wrong hands. We know nothing yet as to whether Smelly's current circuits work or not. I predicted the cap would blow and indeed it did. Chris
  7. chris w

    Fridge Decision

    Warm "Pol Roger '96 Winston Churchill" ........... to what is the world coming? Chris
  8. The 3 most common causes, apart from the man-made hair problem listed above are probably: 1. Blown diode = new rectifier = £15 on Ebay 2. Faulty regulator = new regulator = £10 on Ebay 3. Worn brushes after long service = might as well replace the whole regulator (which usually includes the brush assembly = £10 on Ebay At the end of the day, a whole new alternator can be had on Ebay for around £40 - £70 depending on which day you look. Chris
  9. Your "thermodynamic warning light" is flashing because you only did "O" level physics presumably. This is big boys' stuff. No, it's not perpetual motion owing to the inefficiency of producing the electricity to electrolyse the hydrogen in the first place. You need to understand the effect of increasing entropy on a closed system. Since the entropy increases in the process of electrolysis, an amount of energy can be provided from the environment at temperature T degK. The amount which must be supplied by the battery is actually the change in the "Gibbs free energy" (note: Gibbs, not Gibbo ) Thus the environment "helps" the process by contributing an amount equivalent to 17% of the apparent energy per mole at typical room temperature (~300deg K). The usefulness of the Gibbs free energy is that it tells you what amount of energy in other forms must be supplied to get the process to proceed. The overall efficiency is still less than 100%, but can be very close to 100% as there is no thermodynamic limit to efficiency, as would be implied if the process were linked to a Carnot cycle. Chris
  10. I agree that my version needs soldering and the removal of the regulator. But Smelly doesn't seem phased by these operations based on his dialogue. My circuit also allows paralleling batteries for starting....................and, the other issue,........ it works. Chris
  11. No - that's a small amount of energy. 237KJ is only 5.5% of that 4.3MJ. What you have also overlooked is that it's important to realize that the environment (at typical ambient temperature) contributes thermal energy equal to 48.7 kJ per mole to the hydrogen electrolysis process. That's a 17% contribution "for free". So a full battery can actually cause the electrolysis of 400cc of water if it is not recharged. I probably put in half a litre of water a year spread over 3 x domestics and 1 x start battery. Let's ignore the start battery. So, based on your figures, (and allowing for the "free energy" which you forgot) the amount of energy from the batteries needed to electrolyse that amount is only around 5.5MJ PER YEAR, ie: 1.8MJ per battery per year or 100KJ per cell per year. Your comparison of the necessary energy to the amount of energy in a battery is a red-herring because the battery is continuously charged and does not just have 4.3MJ available. The energy taken from the battery bank over a typical boating year, even by a non-liveaboard, will be in the region of 2 x 109 Joules (ie: 2 BILLION Joules) per year. The 5.5MJ needed to electrolyse 0.5 litres of water over a year is just 0.3% of the total energy used. Even if we say we have underestimated the amount of water needed to top up - let's say it's really 2 litres, not half a litre, the amount of energy taken from the total battery bank as compared to typical use over a year is only around 1.2%. Further, a goodly proportion of this will be due to evaporation and not electrolysis. So, it's a tiny amount of energy - not a (Gibbo) HUGE amount and charging at 14.8v is not wasting energy - it's a red herring. Chris
  12. So you're BACKPEDALLING now on your "HUGE amounts of energy are needed". I note that no mention of the word "HUGE", with regard to the amount of energy needed, has crept into your latest missives. Let's use again your figure of 273KJ - how is that HUGE Gibbo? That's the equivalent of burning one teaspoon of diesel. Huh!!!!!!!!?????????????? The reason so little water is lost is because the effect is negligible. Try studying the philosophy behind "Occam's Razor" Chris
  13. Why all the faffing around with capacitors and light bulbs? The way I did it was so simple..... my switching circuit works immediately (see original diagram) with no problems at all and using the regulator output transistor collector of the alternator with the PDAR connected, to achieve auto switch-off, works beautifully (thanks for Snibble's idea). You seem to understand what needs to be connected where, in this regard Smelly, as you correctly described the mods needed somewhere above. It works, it's not difficult for you, you have all the bits... just go do it - no issues and switches off everytime at 14.35v. Chris
  14. Yeah.... and YOU calculated it at 0.3v, so you must be mortified that YOUR own article doesn't agree with you. I still stand by my calculations. But even if we take your (erroneous) calculations of 237KJ of energy, do you not understand that this is NOT a huge amount of energy as you keep wrongly stating. It is a tiny amount of energy (it's just a large sounding number to the layman). You keep going on about HUGE amounts of energy, I don't think that you understand Joules. 273KJ is the equivalent of burning 6 grams of coal. Go on work it out, if you can. Ergo, running a charger at 14.8v with wet lead-acid batteries does NOT consume HUGE amounts of energy in electrolysis whether one uses my figure or your 10 times smaller figure. Go figure! (Now the beach is calling). Chris
  15. The sound of silence is because I am currently enjoying the sound of waves lapping on a beach and 30degC temperatures. Even the Forum is not a priority at the moment. The article calculated 1AH per 0.33cc...... I calculated 3AH per 1cc.................er......I believe those figures are identical You keep shooting yourself in the foot, because if you were correct with your 237KJ figure then it requires 10 times LESS energy to electrolyse water - so your HUGE is actually HUGE/10 and since your original HUGE was actually SMALL, it's now miniscule. Chris
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