Jon Posted October 8, 2004 Report Share Posted October 8, 2004 FOR ORIGINAL THREAD, SEE HERE Link to comment Share on other sites More sharing options...
Tommo Posted October 8, 2004 Report Share Posted October 8, 2004 FOR ORIGINAL THREAD, SEE HERE <{POST_SNAPBACK}> Richard You are allowed a 4% voltage drop. On 230 Volt that works out at 9.2V, but this is overall including shore line etc.. I would advise that you allow about an 4 volt drop on the internal wiring. By the way, single phase is always calculated at being 230 volt these days. Regards Tommo (Electrican for more years than I care to remember !) Link to comment Share on other sites More sharing options...
Jon Posted October 8, 2004 Author Report Share Posted October 8, 2004 Tommo, Congratulations on having the first post (that wasn't me) on the new forum system! Jon Link to comment Share on other sites More sharing options...
John Orentas Posted October 8, 2004 Report Share Posted October 8, 2004 Richard. The volt drop calculation is the same as before: Amps x Ohms per mtr = Volt drop per mtr. Of course in practise the current (amps) is likely to be lower for a 230 volt circuit which will give a lower volt drop. John Squeers. Link to comment Share on other sites More sharing options...
ChrisPy Posted October 9, 2004 Report Share Posted October 9, 2004 Richard re. the bath. Is it AC or DC? You've really got me worried now, because I haven't allowed space for installing a free-standing whirlpool. I'll just have to look for some powerful weirs. Link to comment Share on other sites More sharing options...
timboharticus Posted October 9, 2004 Report Share Posted October 9, 2004 Re. Volt drop. 4% is used in buildings for 230V systems = 9.2V see Tommo above. Where does the 0.5V for 12V systems come from? Is it a regulation or good practise? 1.5 mmsq has volt drop of 29mV/A/m 2.5 mmsq 18 4 11 6 7.3 These are for copper pvc cables and are for single conductor so need to double up there and back. Actual volt drop is likely to be less as these figures are at max current carrying capacity of cable. So, for a typical lighting load say 40W, volt drop of 50m of cable (total) Power (W) = I(Amps) x V Amps = W/V = 40/12 = 3.3 Amps Current carrying capacity of 1.5mm cable is about 12Amps so no problem here. Volt drop will be 29mV x 3.3 Amps x 50m = 4785mV = 4.8V too high if 12V system ok if 230V system. If we half the load to 20W and use 2.5mm cable get Amps = 20/12= 1.67 Amps Volt drop = 18mV x 1.67Amps x 50m = 1.5Volts still a bit high for 12V system. Suggest wiring in 2.5mm in a ring circuit. This would give a volt drop of about 1V. Perhaps my assumed cable length is a bit long. Link to comment Share on other sites More sharing options...
John Orentas Posted October 9, 2004 Report Share Posted October 9, 2004 xx Link to comment Share on other sites More sharing options...
John Orentas Posted October 9, 2004 Report Share Posted October 9, 2004 xx Link to comment Share on other sites More sharing options...
John Orentas Posted October 9, 2004 Report Share Posted October 9, 2004 <{POST_SNAPBACK}> WHY DOES IT KEEP REPEATING THE ORIGINAL THREAD. I AM OBVIOUSLY DOING SOMETHING WRONG. THE FIRST TIME I CLICK 'REPLY' IT DOESN'T GIVE ME A BOX, I CLICK IT AGAIN AND THIS HAPPENS PLEASE ADVISE JOHN SQUEERS Link to comment Share on other sites More sharing options...
Bernie Posted October 9, 2004 Report Share Posted October 9, 2004 You are doing nothing wrong John, I found this out by accident. Instead of clicking the "REPLY button bottom R scroll down to the very bottom and click the ADD REPLY button, you will then find you don't get the quotes in your message. Bernie. Link to comment Share on other sites More sharing options...
Jon Posted October 10, 2004 Author Report Share Posted October 10, 2004 Am trying to sort this out John. Please bear with me. Jon Link to comment Share on other sites More sharing options...
Richard Bustens Posted October 11, 2004 Report Share Posted October 11, 2004 Hi John So i use the same formular as for 12v ?and that means that a volt drop of 2/3 volts is to high for safty? This is only a prob on the gen set to dist box and the dist box to cooker so far and this gives me a volt drop of 3v and 1.5 v respectiveley. or should i add th cable length together ie:- from genset to cooker adding the two lengths together as one then it gives me 4.5 v drop, Regards Richad. Link to comment Share on other sites More sharing options...
John Orentas Posted October 11, 2004 Report Share Posted October 11, 2004 Richard. As Tommo says your are allowed up to 4% (9 volts) on 230 volt sytems. I don't know where you have got these 'maximun allowed' figures from for you 24 volt circuits, it all depends what equipment you are powering. 3 and 1.5 volt drops in 230 are nothing. John Squeers Link to comment Share on other sites More sharing options...
Richard Bustens Posted October 11, 2004 Report Share Posted October 11, 2004 Thanks John i will continue with the knowledge that you said it was ok Chris I was joking about the bath, i was going to put one in but the bathroom was going to have to be so big to make it look right it was not pratical as it is i have only 12' left for the lounge. so i got a corner bath from B&Q our branch is closing down and they open a new superstore in 2 weeks so everything was going cheep like a budgie, got for £150. Link to comment Share on other sites More sharing options...
ChrisPy Posted October 12, 2004 Report Share Posted October 12, 2004 Richard What is the volt drop between the taps and the bathwater? Does it make any difference if you are in the bath, and if you apply 230V or 12V? Link to comment Share on other sites More sharing options...
Richard Bustens Posted October 12, 2004 Report Share Posted October 12, 2004 Depends on how hot the water is! Link to comment Share on other sites More sharing options...
dor Posted October 12, 2004 Report Share Posted October 12, 2004 s'pose it depends on whether the plug is in Link to comment Share on other sites More sharing options...
John Orentas Posted October 12, 2004 Report Share Posted October 12, 2004 Richard used to work on the buses, he was a very good conductor. John Squeers Link to comment Share on other sites More sharing options...
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